a 330 yard long train travelling at 30 mph enters a two mile long tunnel how long will elapse between the moment the front of the train enters the tunnel and the moment the end of the train clears the tunnel thanks for any help
From the first moment (front entering tunnel) it must travel 330 yards til the back end is just entering the tunnel, then 2 more miles til the back end exits the tunnel so it must travel 2 mile + 330 yards. 1 mile = 1760 yards, so 330 yards = 330/1760 = 0.1875 miles. So it travels 2.1875 miles @ 30 mph (or 0.5 mpm, miles per minute). Time = distance/speed so answer is 2.1875miles/0.5 mpm= 4.375 minutes or 4 mins 22.5 secs.