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Dee-M-See | 23:28 Tue 01st Apr 2008 | Quizzes & Puzzles
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in a game of 6 a side soccer (5 in field 1 in goal)
they play 2 halves 0f 20 minutes long
each team has 4 subs, each player is subbed so that all players are on the pitch the same length of time,how long is each player on the pitch?
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Theory would seem to work , practise does not .
Each team has 240 (6x40) player-minutes to fill, shared between 10 players, so that's 24 minutes per player.

Chris
6 men for 40 minutes = 240 man-minutes

10 players share this so answer = 24 minutes each

I shall now investigate why swannbaker thinks it will not work in practice.
at the minute i agree with swannbaker-the 4 subs can only replace 4 other players-so 2 players would have to play the whole game ?
It depends upon the rules of substitution. It is possible so long as a substitute can go on for 8 minutes, come off and then go back on again for 16 minutes later - also, as long as a player who comes off when a substitute goes on, is allowed to return to the field at a later stage in the game.
Question Author
Sorry about the confusion but the question wording is as it was given to me, I am assured it is not an April Fool joke, although if it is then I am the fool, but I shall give the correct answer when it is given to me, thanks for your answers so far
Question Author
Thank you for your answers it seems that 24 minutes was the answer they were looking for
And so , gen2 , as the manager/ess of this football team , how many players would you have to pull off three times ?
None would have to be pulled off 3 times
Just 4 players would have to come off and go on again later.

The game starts with players 1 - 6 on the field and reserves A B C D at the side

after 8 mins call off 2 and 5 substitute B and C
after 16 mins call off 3 and 4 substitute A and D
after 24 mins call off 1 and 6 substitute 2 and 5
after 32 mins call off B and C substitute 3 and 4

so on the field during each 8 minute section are:-

1... 1... 1... 2... 2
2... C.. D.. D... D
3... 3.. C.. C... 3
4... 4.. B.. B... 4
5... B... A.. 5... 5
6... 6... 6.. A... A

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