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Ones And Noughts

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kuiperbelt | 21:44 Fri 12th May 2023 | Science
17 Answers
From the link below:

https://ibb.co/C2nsfgd

a.) Find the Binary number represented by ???

b.) Having found ???, multiply this by 20 (base 10) and display your result in hexadecimal.

c.) The long division shown gives a complete answer. Multiply this by 100 (base 10) and represent it in Octal.


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ok I see what c) means now, so it should be 5.2 x 100 = 520 = 1010 in Octal 208 in hex. jj 101 is still 5 in binary NOT 6.
14:14 Sat 13th May 2023
a) 101
b) 64
c) 764
Question Author
Well Jim, like in the song, 2 out of 3 aint bad!!

:-)
a) 101 (26/5 decimal 5 remainder 1)
b) 64 (5x20)
c) I don't really understand the question but I think it means 5x100 = 500 or 764 in Octal or 1F4 in hex.
"2 out of 3 ain't bad"

Which one did I get wrong?
I'm going to say that the third one might be 1010_8 = 520_10 = 5.2*100, but with no confidence, because the wording of the third part seems a little clumsy to me.
c) I am not sure what is required but 1130
My rationale 101 remainder 1 binary = 6 (base 10)
multiply by 100 = 600
600 = 1*512, 1*64, 3*8
=1130
101 binary = 5
TTT
The long division shown gives a complete answer.

The complete answer was 101 remainder 1
Question Author
>13.44 - Part c
I'd love to understand the rationale behind that answer. 13.44 in base 8 = 11.5625 in decimal, which is so totally divorced from this question that it caused a split in the Mathematical church.
ok I see what c) means now, so it should be 5.2 x 100 = 520 = 1010 in Octal 208 in hex.
jj 101 is still 5 in binary NOT 6.
I can't see how 13.44 is the answer to c)
the "complete answer" it refers to is 5r1 or 5.2 isn't it?
OMG I'm such a berk, 13.44 is the time of JimF's question :/

Also, well done TTT for getting BA for repeating my answer at 13.47 :P
Question Author
What I particularly liked about this question was the final answer in Octal appearing like a binary number!!

Well done TTT !!
CTG: "OMG I'm such a berk, 13.44 is the time of JimF's question " - snap, I did the same but he did use a . where the : should be! That's my excuse.
TTT I know that 101 = 5 in binary - I just got the remainder wrong, when dividing by "5" the remainder = 0.2 and not 1!

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