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e=mc2

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helle | 01:55 Thu 06th Apr 2006 | Science
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Sorry for being stupid, but if the speed of light is the maximum possible speed then it can't be multiplied with itself. I don't understand.
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Struck a nerve there....
Nobody's saying that anything can travel at a speed which is equal to the square of the speed of light, just that to calculate "E" you multiply mass by a number. That number could be any number at all, and it happend to be c�.

If that troubles you then stay away from i : the square root of minus 1
;-)
We haven't got around to imaginary numbers yet :(. Some time this year no doubt.
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Idiots. Spend all your time googling stuff, pretending to be clever but your not. You are in fact sad and pathetic 35-40 years olds, single living with your parents, no friends, no life trying to justify your existence by spending all your time here lording it up over fellow idiots and children in the vain hope you will convince yourself life is worth living. I feel sorry for you .
Spacechimp 1� 0 → ∞ because....
1/0.1 = 10
1/0.01 = 100
1/0.001 = 1000
1/0.0001 = 10000
1/0.000001 = 100000
as the divisor gets closer to zero the dividend tends towards infinity - it's beyond the scope of calculators hence the math error
no googling required helle - stick that in you pipe and smoke it!
that first line should read 1/0 tends towards infinite
I know that 1/0 is infinity; somebody said that you could have infinity + 1, which is impossible, so I said "math error" (which was clearly from the calculator because any good Englishman knows that would be "maths error").

Hello helle, It's like when you square the lengths of the adjacent sides of a right triangle to find the length of a hippopotamuses hypotenuse. This does not in effect affect the length or the shape of a hypnotized hippopotamuses hypotenuse (or the hippopotamuses bottom musses for that matter). But thanks to the proven genius of Euclidian hypothesis, when we dig down deep into the square root of the sum of the times, we find the Hippocratic hippos hypotenuse is even larger than either of his/her/its other two sides!


Don't know how right this answer is ungooglelized, bye!

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