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Maths Challenge

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derrynoose | 09:04 Fri 16th Oct 2009 | Science
8 Answers
I have been challenged to use the digits 1 to 9 inclusive, in order, and the symbols plus,minus, multiply,divide, to obtain the result 200. So far, no success. Any clear thinking mathematicians out there at this hour?
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I've managed single digits without brackets:-
-1*2 + 3 + 4*5*6 + 7 + 8*9
This assumes the normal rule: multiplication before addition.
21:39 Sat 17th Oct 2009
Lots of ways, but if you aren't allowed brackets, how about
1+234 -5 -6 -7 -8 -9?
Or must you use + - * / just once each?
I bet you'd like to find an answer yourself. So try completing this (the "2" should be written as a superscript, i.e. the first term is one squared):
1(2) *34 *5 ...
Question Author
Thanks Rev.Green. Can complete using your prompt,thanks. I have responded to my challenge setter who queries whether it is possible to come up with a solution using separate digits i.e. not compounding the digits into such as 234 or 23, but using each singly!
what are the rules? Ok each digit individually, what about the operators? must we use at least one of add subtract multiply divide or all of them?
and are we ignoring the normal order of priotity:

eg is 6+7x2 = 26 or 20?
I can\'t manage single digits unless you allow brackets.
With brackets the first six digits can easily make the number 2, and then 200 = 2**7 + 8*9 (the seven is a superscript.
If you need to use all four signs you could have ((-1 * 2 / 3 - 4 + 5) * 6)**7 + 8*9
I've managed single digits without brackets:-
-1*2 + 3 + 4*5*6 + 7 + 8*9
This assumes the normal rule: multiplication before addition.
Question Author
Excellent Rev Green! Go to the top of the class. ( If you're not already there!).

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