Donate SIGN UP
Home > Science > Rain Drop

Rain Drop

Avatar Image
abyss43 | 15:28 Wed 22nd Oct 2008 | Science
3 Answers
How could I as accurately as possible calculate the impulse exterted on a surface by a falling raindrop assuming its impact velocity is 10m/s. (assume water is fresh water at 10 Degress celcius) and impact surface is rigid. Dynamic viscosity water spread etc should be taken into account.
prev briefly explaining the defferent traditional practices each involving a plant,a bird,an animal that reflect our culture of caring for the enviroment
  
next Speed of electricity
Gravatar

Answers

1 to 3 of 3rss feed

Best Answer

No best answer has yet been selected by abyss43. Once a best answer has been selected, it will be shown here.

For more on marking an answer as the "Best Answer", please visit our FAQ.
Avatar Image abyss43
Question Author
Sorry I forgot mass of rain drop is 3 grams
15:45 Wed 22nd Oct 2008
Avatar Image MatydaLover
The force F on the surface will be F = ma ... a being the deceleration v/t. This gives the impulse of the force as Ft = mv ... ... which looks right because the impulse is related to the change in momentum.

It does not matter how long the raindrop takes to stop ... at the end its momentum is zero, so the impluse is mv. with your numbers that is 0.003 kg x 10 m/s 0.03 N (I think it is Newtons).
16:53 Wed 22nd Oct 2008
Avatar Image MatydaLover
... I meant Ns, Newton seconds.
16:55 Wed 22nd Oct 2008

1 to 3 of 3rss feed

Do you know the answer?

Rain Drop

Answer Question >>