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brian j john | 13:28 Sun 07th Nov 2021 | Gaming
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What are the odds of picking three different numbers between 1 and 24

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Does this help? https://www.omnicalculator.com/statistics/combination
13:37 Sun 07th Nov 2021
If you mean three different specified numbers in any order, the odds are 2023/1.
Three, specified, order doesn't matter: 6/(24*23*22) = 1/2024 (ie 2023 to 1).

Three, specified, order *does* matter: 1/(24*23*22) = 1/12144

Three, unspecified: 23*22/(24*24) = 506/576 = 253/288 (about 0.878, or 87.8%).
Depends how they are chosen, of course. If they are chosen from, say, a bag of balls with numbers on them and each ball is left out of the bag when chosen, then picking three different ones is a certainty. If you replace the ball after it has been chosen and pull another at random, then the odds of choosing three different ones are as Jim has explained.
I make it 87.84% (23/24)*(22/24)
sorry (23/24)*(22/24)*100
Depends whether you mean 3 particular numbers or if you mean you pick one replace it and pick again then replace and pick again, and want the odds that there are no duplicate's picked.
Also depends whether there are other numbers in the pot but your just wanting odds of getting numbers 1 to 24.

Maybe your better off telling us the actual senario exactly
N/J @13.27 " Bag of balls " Love it.
^Sounds like the sort of thing my 8 year old nephew would of find hilarious a few years ago

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