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Math Question

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BiennialTable0 | 05:02 Thu 26th May 2016 | Business & Finance
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There are 21 coins - consisting of pennies, nickels, dimes, and quarters. If the pennies were nickels, the nickels were dimes, the dimes were quarters, and the quarters were pennies, the amount of money would stay the same.

How much money is there?
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Fibonacci
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I have found four possible solutions: pennies,nickels,dimes,quarters 9,6,2,4 = $1.59 10,1,5,5 = $1.90 1,7,7,6 = $2.56 2,2,10,7 = $2.87
07:05 Thu 26th May 2016
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Avatar Image Old_Geezer
Sounds a nice puzzle too solve. But too early in the morning here to go looking up the values of the stated coins.
05:08 Thu 26th May 2016
Avatar Image Old_Geezer
Probably should be in 'Quizzes & Puzzles' forum really.
05:09 Thu 26th May 2016
Avatar Image Fibonacci
I have found four possible solutions:
pennies,nickels,dimes,quarters
9,6,2,4 = $1.59
10,1,5,5 = $1.90
1,7,7,6 = $2.56
2,2,10,7 = $2.87

07:05 Thu 26th May 2016
Avatar Image fiction-factory
Hi. Did you get chance to look at the answers you got yesterday to your Word Puzzles?
07:13 Thu 26th May 2016

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