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Mags22 | 19:47 Fri 04th Apr 2014 | Quizzes & Puzzles
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Farmer goes to market and pays £100 for 100 animals.Cows cost £10,sheep £1,and chickens 12.5 each,how many of each does he buy? Could this be trick question ? Can anyone work answer it,and give explanation please?
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7 cows= £70 21 sheep= £21 72 chickens=£9 Total =l £100
20:02 Fri 04th Apr 2014
100 sheep would work.
Are the chickens 12.5 p each?
100 sheep?
can he not just buy 100 sheep ?
Does he have to buy some of each? If so the number of chickens must be a multiple of 8.
I'll have a think after corrie
7 cows= £70
21 sheep= £21
72 chickens=£9
Total =l £100
I knew that simultaneous equations would come in useful one day
Lol. I remember those...
nice one ff, I had cows sheep and chickens running about everywhere !!
or
144 chickens = £18
2 Sheep = £2
8 Cows = £80

Total = £100
Except that's 154 animals, Mamya
Detention for me, whoops.
keep up, mama.lol.
i tried for a bit, but thought sod it, i'll wait for factor.
Well done Factor! Could you please detail how you solved it??
I now have a surfeit of chicken for Sunday lunch , all are welcome.
Question Author
What are simultaneous equations, you got me baffled now guys,.will wait till after ' Corrie ' ,factorfiction, Maths were never my strong point
let W, S and C be the numbers of coWs, Sheep and Chickens
10W+S+0.125C=100
multiply throughout by 8:
80W +8S +C= 800 (equation 1)

Also we know W+S+C= 100 (equation 2)

Subtract equation 2 from equation 1:
79W+7S=700
so 79W= 700-7s
So W (number of cows)must be multiple of 7

As cows cost £10 each the only possible answer (other than W=0) is w=7
That means 7S= 147 so S =21

Can then work out C
Question Author
Oh heck factor-fiction,I'm totally baffled now ,obviously was more interested in the boy beside me in maths lessons,and am much better with words than numbers, but am going with your brilliant answer, thank you and everyone else for taking my mind off Tina's plight,when will she see Peter is a right prat?

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